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Program to sum of N natural number

Input - Output

Input
Enter range to calculate sum of natural no. : 10

Output
Sum of first 10 natural number are : 55

Algorithm

Step 1: START

Step 2: Enter range to print natural number

Declare and initializing another variable sum=0 .

Step 3: Apply Condition: for(i=1;i<=num;i++)

          sum=sum+i;

Step 4: Print sum.

Step 5: END

CODE


/* Print sum of N natural number */

#include<stdio.h>
int main()
{
      int num,sum=0;
      printf(" Enter an integer number : ");
      scanf("%d",&num);
      for(int i=1;i<=num;i++)
      sum = sum + i;
      printf(" Sum of first %d natural numbers = %d",num,sum);
    return 0;
}


/* Print sum of N natural number */

#include<iostream>
using namespace std;
int main()
{
      int num,sum=0;
      cout<<" Enter an integer number : ";
      cin>>num;
      for(int i=1;i<=num;i++)
      sum = sum + i;
      cout<<" Sum of first "<<num<<" natural numbers = "<<sum;
    return 0;
}

OutPut

Enter range to calculate sum of natural no. : 10

Sum of first 10 natural number are : 55

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