Input
Enter two intervals : 20 500Output
Armstrong number between 20 and 500 are : 153 3370 371 407Step 1: START
Step 2: Declare variable low,high,i,rem,temp1,temp2,n=0
Step 3: Enter interval and store it into low and high.
Step 4: Check each number one by one.
step 6: End
/* Print all Armstrong number in a given range */
#include<stdio.h>
#include<math.h>
int main()
{
int low,high,i,rem,temp1,temp2,n=0;
float result = 0.0;
printf(" Enter two intervals : ");
scanf("%d %d", &low, &high);
printf(" Armstrong numbers between %d and %d are : ",low,high);
for(i=low+1;i<high;++i)
{
temp1 = i;
while(temp1 != 0)
{
temp1 /= 10;
++n;
}
temp2 = i;
while(temp2 != 0)
{
rem = temp2 % 10;
result += pow(rem,n);
temp2 /= 10;
}
if((int)result == i)
{
printf(" %d ",i);
}
n=0;
result=0;
}
return 0;
}/* Print all Armstrong number in a given range */
#include<iostream>
#include<math.h>
using namespace std;
int main()
{
int low,high,i,rem,temp1,temp2,n=0;
float result = 0.0;
cout<<" Enter two intervals : ";
cin>>low>>high;
cout<<" Armstrong numbers between "<<low<<" and "<<high<<" are : ";
for(i=low+1;i<high;++i)
{
temp1 = i;
while(temp1 != 0)
{
temp1 /= 10;
++n;
}
temp2 = i;
while(temp2 != 0)
{
rem = temp2 % 10;
result += pow(rem,n);
temp2 /= 10;
}
if((int)result == i)
{
cout<<" "<<i;
}
n=0;
result=0;
}
return 0;
}Enter two intervals : 20 500
Armstrong number between 20 and 500 are : 153 3370 371 407
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