Input
Enter value of n and r : 5 2Output
permutaion : 20Input
Enter value of n and r : 6 3Output
permutaion : 120Step 1: START
Step 2: Enter 'n' and 'r'as input.
Step 3: calculate n! and (n-r)! separately
use formula of permutaion npr=n!/(n-r)!
Step 5:print permutaion .
Step 6: END
/* Program to calculate permutaion */
#include<stdio.h>
long permutaion(int n, int r);
long factorial(int num);
int main()
{
int n,r;
printf(" Enter the value of n : ");
scanf("%d",&n);
printf(" Enter the value of r : ");
scanf("%d",&r);
printf(" Permutaion is : %ld",permutaion(n,r));
return 0;
} long permutaion(int n,int r)
{
return factorial(n) / factorial(n-r);
}
long combination(int n,int r)
{
return permutaion(n,r) / factorial(r);
}
long factorial(int num)
{
long long fact =1;
while(num > 0)
{
fact = fact * num;
num--;
}
return fact;
}
/* Program to calculate permutaion */
#include<iostream>
using namespace std;
long permutaion(int n, int r);
long factorial(int num);
int main()
{
int n,r;
cout<<" Enter the value of n : ";
cin>>n;
cout<<" Enter the value of r : ";
cin>>r;
cout<<" Permutation is : "<<permutaion(n,r);
return 0;
} long permutaion(int n,int r)
{
return factorial(n) / factorial(n-r);
}
long combination(int n,int r)
{
return permutaion(n,r) / factorial(r);
}
long factorial(int num)
{
long long fact =1;
while(num > 0)
{
fact = fact * num;
num--;
}
return fact;
}
Enter the value of n : 5 Enter the value of r : 2
Permutaion is = 20
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