Input
Enter a decimal number : 9Output
Binary equivalent of given number : 1001 Input
Enter a decimal number : 12Output
Binary equivalent of given number : 1100Step 1: START
Step 2: Enter a number 'num' as an input.
Step 3: Calculate remainder i.e(num%2) and store it into an array
Step 4: Divide the num by 2 i.e (num/2)
Step 5: Repeat the step 3 and 4 until the num is greater than zero
Step 6: END
/* Decimal to Binary Conversion */
#include <stdio.h>
int main()
{
int num,bin[10],i,j;
printf(" Enter the decimal number : ");
scanf("%d",&num);
for(i=0;num>0;i++)
{
bin[i]=num%2;
num/=2;
}
printf(" Binary of given number is = ");
for(j=i-1;j>=0;j--)
printf("%d",bin[j]);
return 0;
}/* Decimal to Binary Conversion */
#include <iostream>
using namespace std;
int main()
{
int num,bin[10],i,j;
cout<<" Enter the decimal number : ";
cin>>num;
for(i=0;num>0;i++)
{
bin[i]=num%2;
num/=2;
}
cout<<" Binary of given number is = ";
for(j=i-1;j>=0;j--)
cout<<bin[j];
return 0;
}Enter the decimal number: 9
Binary of given number is = 1001
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