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Program to print reverse of N natural number

Input - Output

Input
Enter maximum limit to print natural no : 5

Output
Reverse order of natural no : 5 4 3 2 1

Algorithm

Step 1: START

Step 2: Enter maximum limit to print natural number

Step 3: Apply Condition: for(i=num;i>=1;i--)

        print i;

Step 4: END

CODE


/* Print reverse of N natural number */

#include<stdio.h>
int main()
{
      int num;
      printf(" Enter an integer number : ");
      scanf("%d",&num);
      printf(" Reverse of N natural number :");
      for(int i=num;i>=1;i--)
      printf(" %d ",i);
    return 0;
}


/* Print reverse of N natural number */

#include<iostream>
using namespace std;
int main()
{
      int num;
      cout<<" Enter an integer number : ";
      cin>>num;
      cout<<" Reverse of N natural number : ";
      for(int i=num;i>=1;i--)
      cout<<" "<<i;
    return 0;
}

OutPut

Enter maximum limit to print natural no : 5

Reverse order of natural no : 5 4 3 2 1

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