PLAY WITH CODING

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Program Based on If & Else

Program to count number of vowel in a string

Input - Output

Input
Enter a string : playwithcoding

Output
Number of vowel = 4

Algorithm

Step 1: START

Step 2: Declare a variable count=0;

Step 3: Enter a string as an input.

Step 4: Check each character of the string:

    if ch[i]=A,E,I,O,U or a,e,i,o,u

       count++;

Step 5: Print count

Step 6: END

CODE


/* Count number of vowel */
#include  <stdio.h>
int main()
{
      int count=0;
      char str[10];
      printf(" Enter a character : ");
      scanf("%s",str);
      for(int i=0;str[i];i++)
          if(str[i]=='A'||str[i]=='a'||str[i]=='E'||str[i]=='e'||str[i]=='I'||str[i]=='i'||str[i]=='O'||str[i]=='o'||str[i]=='U'||str[i]=='u')
              count++;
     printf(" number of vowel present in %s = %d",str,count);
    return 0;
}


/* Count number of vowel */
#include <iostream>
using namespace std;
int main()
{
      int count=0;
      char str[10];
      cout<<" Enter a character : ";
      cin>>str;
      for(int i=0;str[i];i++)
          if(str[i]=='A'||str[i]=='a'||str[i]=='E'||str[i]=='e'||str[i]=='I'||str[i]=='i'||str[i]=='O'||str[i]=='o'||str[i]=='U'||str[i]=='u')
              count++;
     cout<<" number of vowel present in "<<str<<" = "<<count;
    return 0;
}

OutPut

Enter a string : playwithcoding

Number of vowel = 4

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