Input
Enter a Binary number : 1001Output
Decimal equivalent of given number : 9 Input
Enter a Binary number : 1100Output
Decimal equivalent of given number : 12Step 1: START
Step 2: Enter a binary number 'num' as an input.
Step 3: Multiply each digit of num by the power of 2 and store each multiplication.
i.e Power of 2 starts from 0 to n-1 where n is the total number of digits in the num
Step 4: END
/* Binary to Decimal Conversion */
#include <stdio.h>
#include <math.h>
int main()
{
int bin,decimal=0,rem,i,j;
printf(" Enter the binary number : ");
scanf("%d",&bin);
for(i=0;bin>0;i++)
{
rem=bin%10;
decimal=decimal+rem*pow(2,i);
bin/=10;
}
printf(" decimal of given number is = %d",decimal);
return 0;
}/* Binary to Decimal Conversion */
#include <iostream>
#include <math.h>
using namespace std;
int main()
{
int bin,decimal=0,rem,i,j;
cout<<" Enter the binary number : ";
cin>>bin;
for(i=0;bin>0;i++)
{
rem=bin%10;
decimal=decimal+rem*pow(2,i);
bin/=10;
}
cout<<" decimal of given number is = "<<decimal;
return 0;
}Enter a Binary number : 1001
Decimal equivalent of given number : 9
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