Input
Enter a number of days : 781Output
No. of years = 2 No. of months= 1
No. of days= 21
Step 1: START
Step 2: input number of "days" as input.
Step 3: declare a third variable as years and months.
Step 4: calculate years=days/365
Step 5: calculate the remaining days=days%365
Step 6: calculate months=days/12
Step 7: calculate the remaining=days%12
Step 8: Print the years , months and days
Step 9: END
/* convert days into years ,months and days */
#include <stdio.h>
int main()
{
int days,years,months;
printf("Enter number of days: ");
scanf("%d",&days);
years=days/365;
days=days%365;
months=days/30;
days=days%30;
printf("No.of years = %d\n",years);
printf("No.of months = %d\n",months);
printf("No.of days = %d\n",days);
return 0;
}/* convert days into years , months , days */
#include <iostream>
using namespace std;
int main()
{
int days,years,months;
cout<<"Enter number of days: ";
cin>>days;
years=days/365;
days=days%365;
months=days/30;
days=days%30;
cout<<"No.of years = "<<years<<"\n";
cout<<"No.of months = "<<months<<"\n";
cout<<"No.of days = "<<days<<"\n";
return 0;
}Enter a number of days : 781
No.of years = 2
No.of months= 1
No.of days= 21
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